Physics equations/Sheet/All chapters

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00-Mathematics_for_this_course

   Measured in radians, \theta = s/r defines angle (in radians), where s is arclength and r is radius. The circumference of a circle is C_\odot = \,2\pi r and the circle's area is A_\odot = \,\pi r^2 is its area. The surface area of a sphere is A_\bigcirc = 4\pi r^2 and sphere's volume is V_\bigcirc = \frac{4}{3}\pi r^3

    A vector can be expressed as, \vec A = A_x \, \hat i+ A_y \, \hat j, where A_x=A\cos\theta, and A_y=A\sin\theta are the x and y components. Alternative notation for the unit vectors (\hat i, \hat j) include (\hat x, \hat y) and (\widehat {e_1}, \widehat {e_2}). An important vector is the displacement from the origin, with components are typically written without subscripts: \vec r = x\hat x + y\hat y. The magnitude (or absolute value or norm) of a vector is is A \equiv |\vec A|= \sqrt{A_x^2 + A_y^2} \quad, where the angle (or phase), \theta, obeys \tan\theta=y/x, or (almost) equivalently, \theta = \arctan{(y/x)} \quad. As with any function/inverse function pair, the tangent and arctangent are related by \tan(\tan^{-1}\mathcal X) = \mathcal X where \mathcal X = y/x. The arctangent is not a true function because it is multivalued, with \tan^{-1}(\tan \theta) = \theta\; or\; \theta+\pi.

    The geometric interpretations of \vec A +\vec B =\vec C and \vec B = \vec C -\vec A are shown in the figure. Vector addition and subtraction can also be defined through the components: \vec A +\vec B =\vec C \Leftrightarrow A_x + B_x =C_x AND A_y + B_y =C_y 01-Introduction

Text Symbol Factor Exponent
giga G 1000000000 E9
mega M 1000000 E6
kilo k 1000 E3
(none) (none) 1 E0
centi c 0.01 E−2
milli m 0.001 E−3
micro μ 0.000001 E−6
nano n 0.000000001 E−9
pico p 0.000000000001 E−12

Two dimensional kinematics Difference is denoted by d\mathcal X, \delta\mathcal X, or the Delta. \Delta\mathcal X = \mathcal X_f - \mathcal X_i or \mathcal X - \mathcal X_0. Average, or mean, is denoted by \bar{\mathcal X}=\langle \mathcal X\rangle = \mathcal X_\text{ave}=\Sigma \mathcal X_i\mathcal/N \ \text{or} \ \Sigma \mathcal P_i\mathcal X_i, where \mathcal N is number and \mathcal P_i are probabilities. The average velocity is \bar v = \Delta x/\Delta t, and the average acceleration is \bar a = \Delta v/\Delta t, where x denotes position. In CALCULUS, instantaneous values are denoted by v(t)=dx/dt and a=dv/dt=d2x/dt2.

The equations of motion for uniform acceleration are: x= x_0 + v_0t+\tfrac 1 2 at^2, and, v = v_0+at. Also, v^2  = v_0^2 + 2a\left( x - x_0 \right), and, x - x_0   = \tfrac 1 2 (v_0+v)= \bar vt. Note that \bar v = \tfrac 1 2 (v_0+v) only if the acceleration is uniform. 03-Two-Dimensional_Kinematics

x=x_0+v_{0x}\Delta t+\frac{1}{2}a_x\Delta t^2      v_x=v_{0x}+a_x \Delta t      v_x^2=v_{x0}^2+ 2a_x\Delta x
y=y_0+v_{0y}\Delta t+\frac{1}{2}a_y\Delta t^2      v_y=v_{0y}+a_y \Delta t      v_y^2=v_{x0}^2+ 2a_y\Delta y

v^2=v_0^2+ 2a_x\Delta x + 2a_y\Delta y   ...in advanced notation this becomes \Delta (v^2) = 2\vec a\cdot\Delta\vec\ell.

In free fall we often set, ax=0 and ay= -g. If angle is measured with respect to the x axis:

 v_x =  v\cos\theta        v_y =  v\sin\theta        v_{x0} =  v_0\cos\theta_0        v_{y0} =  v_0\sin\theta_0

The figure shows a Man moving relative to Train with velocity, \vec v_{M|T}, where the velocity of the train relative to Earth is, \vec v_{T|E} is the velocity of the Train relative to Earth. The velocity of the Man relative to Earth is,

     \underbrace{\vec v_{M|E}}_{50\;km/hr}=\underbrace{\vec v_{M|T}}_{10\;km/hr}+\underbrace{\vec v_{T|E}}_{40\;km/hr}\, If the speeds are relativistic, define u=v/c where c is the speed of light, and this formula must be modified to: u_{A|O}=  \frac{u_{A|O'}+ u_{O'|O}}{1+ (u_{A|O\,'})(u_{O\,'|O})} 04-Dynamics:_Force_and_Newton's_Laws

Newton's laws of motion, can be expressed with two equations,  m\vec a = \sum\vec F_j  \, and \vec F_{ij}=-\vec F_{ji}. The second represents the fact that the force that the i-th object exerts one object exerts on the j-th object is equal and opposite the force that the j-th exerts on the i-th object. Three non-fundamental fores are:

  1. The normal force, N, is a contact forces that is perpendicular to the surface,
  2. The force of friction, f, is a contact force that is parallel to the surface.
  3. Tension, T, is often associated with ropes and strings. If the rope has sufficiently low weight and of all external forces act at the two ends, then this tension is distributed uniformly along the rope.
  4. The fourth force is fundamental: Weight equals mg, and is the force of gravity acting on an object of mass, m. At Earth's surface, g\approx9.8m/s^2.

     The x and y components of the three forces of tension on the small grey circle where the three "massless" ropes meet are:

T_{1x}=-T_1\cos\theta_1 ,         T_{1y}=T_1\sin\theta_1
T_{2x}=0 ,                             T_{2y}=-mg
T_{3x}=T_3\cos\theta_3 ,          T_{3y}=T_3\sin\theta_3

05-Friction,_Drag,_and_Elasticity

Also, air drag often depends on speed, an effect this model fails to capture. 06-Uniform_Circular_Motion_and_Gravitation

uniform circular motion (here the Latin d was used instead of the Greek Δ

07-Work_and_Energy

08-Linear_Momentum_and_Collisions

09-Statics_and_Torque

The SI units for torque is the newton metre (N·m). It would be inadvisable to call this a Joule, even though a Joule is also a (N·m). The symbol for torque is typically τ, the Greek letter tau. When it is called moment, it is commonly denoted M.[1] The lever arm is defined as either r, or r. Labeling r as the lever arm allows moment arm to be reserved for r. 10-Rotational_Motion_and_Angular Momentum

Linear motion Angular motion
x-x_0 = v_0 t + \frac {1} {2} a t^2  \theta-\theta_0 = \omega _0 t + \frac{1}{2} \alpha t^2
v = v_0+at \,  \omega = \omega _0 + \alpha t \,
x-x_0 = \frac {1} {2}(v_0+v) t  \theta-\theta_0 = \frac{1}{2}(\omega _0 + \omega )t
v^2 = v_0^2 + 2 a (x -x_0)\,  \omega^2 = \omega _0^2 + 2\alpha(\theta-\theta_0)

The following table refers to rotation of a rigid body about a fixed axis: \mathbf s is arclength, \mathbf r is the distance from the axis to any point, and \mathbf{a}_\mathbf{t} is the tangential acceleration, which is the component of the acceleration that is parallel to the motion. In contrast, the centripetal acceleration, \mathbf{a}_\mathbf{c}=v^2/r=\omega^2 r, is perpendicular to the motion. The component of the force parallel to the motion, or equivalently, perpendicular, to the line connecting the point of application to the axis is \mathbf{F}_\perp. The sum is over \mathbf j \ = 1 \ \mathbf{to}\ N particles or points of application.

Analogy between Linear Motion and Rotational motion[2]
Linear motion Rotational motion Defining equation
Displacement =  \mathbf{x} Angular displacement =  \theta  \theta = \mathbf{s}/\mathbf{r}
Velocity =  \mathbf{v} Angular velocity =  \omega  \omega= \mathbf{d}\theta /\mathbf{dt}=\mathbf{v}/\mathbf{r}
Acceleration =  \mathbf{a} Angular acceleration =  \alpha  \alpha= \mathbf{d}\omega / \mathbf{dt}=\mathbf{a_\mathbf{t}}/\mathbf{r}
Mass =  \mathbf{m} Moment of Inertia =  \mathbf{I}  \mathbf{I}=\sum \mathbf{m_j}\mathbf{r_j}^2
Force =  \mathbf{F} = \mathbf{m} \mathbf{a} Torque =  \tau = \mathbf{I} \alpha  \tau = \sum\mathbf{r_j} \mathbf{F}_\perp\mathbf{_j}
Momentum=  \mathbf{p} = \mathbf{m} \mathbf{v} Angular momentum=  \mathbf L = \mathbf{I} \omega  \mathbf L = \sum\mathbf{r_j}\mathbf{p}\mathbf{_j}
Kinetic energy =  \frac 1 2\mathbf{m} \mathbf{v}^2 Kinetic energy =  \frac 1 2\mathbf{I} \omega^2  \frac 1 2 \sum\mathbf{m_j}\mathbf{v_j}^2 = \frac 1 2 \sum\mathbf{m_j}\mathbf{r_j}^2\omega^2
Description[3] Figure Moment(s) of inertia
Rod of length L and mass m
(Axis of rotation at the end of the rod)
I_{\mathrm{end}} = \frac{m L^2}{3} \,\!
Solid cylinder of radius r, height h and mass m I_z = \frac{m r^2}{2}\,\!
I_x = I_y = \frac{1}{12} m\left(3r^2+h^2\right)
Sphere (hollow) of radius r and mass m I = \frac{2 m r^2}{3}\,\!
Ball (solid) of radius r and mass m I = \frac{2 m r^2}{5}\,\!

11-Fluid_statics

Pressure is the weight per unit area of the fluid above a point.

Pressure versus Depth: A fluid's pressure is F/A where F is force and A is a (flat) area. The pressure at depth, h below the surface is the weight (per area) of the fluid above that point. As shown in the figure, this implies:

 P = P_0 + \rho g h

where P_0 is the pressure at the top surface, h is the depth, and \rho is the mass density of the fluid. In many cases, only the difference between two pressures appears in the final answer to a question, and in such cases it is permissible to set the pressure at the top surface of the fluid equal to zero. In many applications, it is possible to artificially set P_0 equal to zero, for example at atmospheric pressure. The resulting pressure is called the gauge pressure, for  P_{gauge} = \rho gh  below the surface of a body of water.

Buoyancy and Archimedes' principle Pascal's principle does not hold if two fluids are separated by a seal that prohibits fluid flow (as in the case of the piston of an internal combustion engine). Suppose the upper and lower fluids shown in the figure are not sealed, so that a fluid of mass density \rho_{flu} comes to equilibrium above and below an object. Let the object have a mass density of \rho_{obj} and a volume of A\Delta h, as shown in the figure. The net (bottom minus top) force on the object due to the fluid is called the buoyant force:

\rm{buoyant}\;\rm{force}=(A\Delta h )(\rho_{flu})g\,,

and is directed upward. The volume in this formula, AΔh, is called the volume of the displaced fluid, since placing the volume into a fluid at that location requires the removal of that amount of fluid. Archimedes principle states:

A body wholly or partially submerged in a fluid is buoyed up by a force equal to the weight of the displaced fluid.

Note that if \rho_{obj}=\rho_{flu}, the buoyant force exactly cancels the force of gravity. A fluid element within a stationary fluid will remain stationary. But if the two densities are not equal, a third force (in addition to weight and the buoyant force) is required to hold the object at that depth. If an object is floating or partially submerged, the volume of the displaced fluid equals the volume of that portion of the object which is below the waterline. 12-Fluid_dynamics

A fluid element speeds up if the area is constricted.

13-Temperature,_Kinetic Theory,_and_Gas_Laws

14-Heat_and_Heat_Transfer Here it is convenient to define heat as energy that passes between two objects of different temperature Q The SI unit is the Joule. The rate of heat trasfer, \Delta Q/\Delta t or \dot Q is "power": 1 Watt = 1 W = 1J/s

15-Thermodynamics

A point on a PV diagram define's the system's pressure (P) and volume (V). Energy (E) and pressure (P) can be deduced from equations of state: E=E(V,P) and T=T(V,P). If the piston moves, or if heat is added or taken from the substance, energy (in the form of work and/or heat) is added or subtracted. If the path returns to its original point on the PV-diagram (e.g., 12341 along the rectantular path shown), and if the process is quasistatic, all state variables (P, V, E, T) return to their original values, and the final system is indistinguishable from its original state.

The net work done per cycle is area enclosed by the loop. This work equals the net heat flow into the system, Q_{in} - Q_{out} (valid only for closed loops).

Remember: Area "under" is the work associated with a path; Area "inside" is the total work per cycle.

CALCULUS:  \oint P \ dV = Q_{in} - Q_{out} .

In an isothermal expansion (contraction), temperature, T, is constant. Hence P=nRT/V and substitution yields,
\int_{Vi}^{Vf}PdV=\int_{Vi}^{Vf}nRT\frac{dV}{V}=nRT\int_{Vi}^{Vf}\frac{dV}{V}=nRT\ln\frac{V_f}{V_i}

16-Oscillatory_Motion_and_Waves

Let  x(t) = x_0\cos\left(\omega_0 t - \varphi\right) = describe position:

17-Physics_of_Hearing

18-Electric_charge_and_field

Consider a collection of N particles of charge Q_i, located at points \vec r_i (called source points), the electric field at \vec r (called the field point) is:

CALCULUS supplement:

  \vec{E}(\vec r)= k_e\int\frac{\hat\mathcal R dQ}{\mathcal R^2} is the electric field due to distributed charge, where  dQ\rightarrow\lambda d\ell\rightarrow \sigma dA\rightarrow\rho dV\;, and (\lambda, \sigma, \rho) denote linear, surface, and volume density (or charge density), respectively.

     Cartesian coordinates (x, y, z). Volume element: dV=dxdydz. Line element:d\vec\ell =\hat x dx+\hat y dy+\hat z dz. Three basic area elements: \hat ndA = \hat z dxdy, or, \hat x dydz , or,\hat y dzdx.

     Cylindrical coordinates (ρ, φ, z): Volume element: dV =\rho\,dr\,d\varphi \,dz . Line element:d\vec\ell =\hat\varphi rd\varphi+\hat r dr+\hat zdz. Basic area elements: \hat ndA = \rho\,d\varphi\,dz\,\hat \rho (side), and, \rho\,d\rho\,d\varphi\,\hat z (top end).

   Spherical coordinates (r, θ, φ): Volume element: dV = r^2\,dr\,\sin\theta\,d\theta\,d\varphi \rightarrow 4\pi r^2dr (if symmetry holds). Line element: d\vec\ell= \hat r \,dr+  \hat\theta\, r\, d\theta +   \hat \varphi\, r\, \sin{\theta} \, d\varphi. Basic area element of a sphere: \hat r dA = \hat r\,r^2 d\Omega, where dΩ is a solid angle. 19-Electric_Potential_and_Electric_Field

CALCULUS supplement

closed surfaces | Ω & Ω
To the left are closed surfaces. To the right are open surfaces, Ω, that possess closed boundaries, Ω.

Here, Ω is a (3-dimensional) volume and Ω is the boundary of the volume, which is a (two-dimensional) surface. Also a surface is Σ, which, if open, has the boundary Σ, which is a (one-dimensional) curve.

20-Electric_Current,_Resistance,_and_Ohm's_Law

21-Circuits,_Bioelectricity,_and_DC_Instruments

The current entering any junction is equal to the current leaving that junction. i2 + i3 = i1 + i4
The sum of all the voltages around the loop is equal to zero. v1 + v2 + v3 - v4 = 0
Resistors in parallel
Resistors in series
voltage divider
In this example, we assume that the rectangular element is a resistor, R, and that the internal resistance of the voltage source (not shown) is also R. The ammeter and voltmeter shown are ideal.
Charging and discharging a capacitor with the alternating switch shown to the left (i.e. where the RC rise and discharge times are equal).

V(t)=V_0 e^{-\frac{t}{RC}} \ ,

where V0 is the capacitor voltage at time t = 0 (when the switch was closed). The time required for the voltage to fall to \frac{V_0}{e}\approx .37V_0 is called the RC time constant and is given by

 \tau = RC \ .

22-Magnetism

  1.   B=\frac{\mu_0 I}{2\pi r} is the magnetic field at a distance r from an infinitely long wire carrying a current, where μ0 = 4π × 10−7 N A. This field points azimuthally around the wire in a direction defined by the right hand rule. Application of the force law on a current element, we have
  2.   F=\frac{\mu_0 I_1 I_2\,\ell}{2\pi r} is the force between two long wires of length \ell separated by a short distance r<<\ell. The currents are I1 and I2, with the force being attractive if the currents are flowing in the same direction.

Cyclotron motion: For a particle moving perpendicular to B, we have cyclotron motion. Recall that for uniform circular motion, the acceleration is a=v2/r, where r is the radius. Since sin θ =1, Newton's second law of motion (F=ma) yields,

ma=\frac{mv^2}{r}=qvB

Since, sin θ =0, for motion parallel to a magnetic field, particles in a uniform magnetic field move in spirals at a radius which is determined by the perpendicular component of the velocity:

r =\frac{mv_\perp}{qB}

Hall effect: The Hall effect occurs when the magnetic field, velocity, and electric field are mutually perpendicular. In this case, the electric and magnetic forces are aligned, and can cancel if qE=qvB (since sinθ = 1). Since both terms are porportional to charge, q, the appropriate ratio of electric to magnetic field for null net force depends only on velocity:

E = vB = \frac{\mathrm{emf}}{\ell},

where we have used the fact that voltage (i.e. emf or potential) is related to the electric field and a displacement parallel to that field: ΔV = -E Δs cosθ

CALCULUS supplement:

23-Electromagnetic_Induction,_AC_Circuits,_and_Electrical_Technologies

In rod's frame the force on carriers is electric, not magnetic. (See railgun)

24-Electromagnetic_Waves

Maxwell's equations hold for all volumes and closed surfaces. In vacuum, electromagnetic waves travel at the speed, c = \frac{1}{\sqrt{\epsilon_0\mu_0}}.

\oint_S  \mathbf{E} \cdot \mathrm{d}\mathbf{A} = \frac{1}{\epsilon_0} \int_V \rho\, \mathrm{d}V \oint_C \mathbf{E} \cdot \mathrm{d}\mathbf{l} = -\int_S \frac{\partial\mathbf{B}}{\partial t} \cdot \mathrm{d} \mathbf{A}
\oint_S \mathbf{B} \cdot \mathrm{d}\mathbf{A} = 0 \oint_C \mathbf{B} \cdot \mathrm{d}\mathbf{l} = \mu_0 \int_S \mathbf{J} \cdot \mathrm{d} \mathbf{A} +
           \epsilon_0\mu_0 \int_S \frac{\partial\mathbf{E}}{\partial t} \cdot \mathrm{d} \mathbf{A}

25-Geometric_Optics

\frac{1}{S_1} + \frac{1}{S_2} = \frac{1}{f}  relates the focal length f of the lens, the image distance S1, and the object distance S2. The figure depicts the situation for which (S1, S2, f) are all positive: (1)The lens is converging (convex); (2) The real image is to the right of the lens; and (3) the object is to the left of the lens. If the lens is diverging (concave), then f < 0. If the image is to the left of the lens (virtual image), then S2 < 0 .

27-Wave_Optics

\bar\omega=\frac{\omega_1+\omega_2}{2} and \Delta\omega=\omega_2-\omega_1. Consequently, the beat frequency heard when two tones of frequency f_1 and f_2 is \Delta f = f_2-f_1.
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