Physics equations/05-Friction, Drag, and Elasticity/Q:thirdLaw/Testbank
Study: http://en.wikiversity.org/wiki/Physics_equations/Sheet/All_chapters
a05frictDragElast_3rdLaw_v1
copies
===2===
{<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.4 kg, and the mass of m<sub>2</sub> is 2.3 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 174 N, what is the tension in the connecting string? Assume no friction is present.}
-a) 84.2 N
-b) 96.8 N
-c) 111.3 N
+d) 128 N
-e) 147.2 N
===3===
{<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 7 kg, and the mass of m<sub>2</sub> is 3.6 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 153 N, what is the tension in the connecting string? Assume no friction is present.}
-a) 66.4 N
-b) 76.4 N
-c) 87.9 N
+d) 101 N
-e) 116.2 N
===4===
{<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.7 kg, and the mass of m<sub>2</sub> is 2.5 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 101 N, what is the tension in the connecting string? Assume no friction is present.}
-a) 55.6 N
-b) 64 N
+c) 73.6 N
-d) 84.6 N
-e) 97.3 N
===5===
{<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 5.4 kg, and the mass of m<sub>2</sub> is 3.9 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 136 N, what is the tension in the connecting string? Assume no friction is present.}
+a) 79 N
-b) 90.8 N
-c) 104.4 N
-d) 120.1 N
-e) 138.1 N
===6===
{<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 5.1 kg, and the mass of m<sub>2</sub> is 2.8 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 148 N, what is the tension in the connecting string? Assume no friction is present.}
+a) 95.5 N
-b) 109.9 N
-c) 126.4 N
-d) 145.3 N
-e) 167.1 N
===7===
{<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 5.4 kg, and the mass of m<sub>2</sub> is 2.3 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 138 N, what is the tension in the connecting string? Assume no friction is present.}
-a) 84.2 N
+b) 96.8 N
-c) 111.3 N
-d) 128 N
-e) 147.2 N
===8===
{<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.5 kg, and the mass of m<sub>2</sub> is 2.5 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 141 N, what is the tension in the connecting string? Assume no friction is present.}
-a) 58.2 N
-b) 67 N
-c) 77 N
-d) 88.6 N
+e) 101.8 N
===9===
{<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 5.1 kg, and the mass of m<sub>2</sub> is 3.5 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 135 N, what is the tension in the connecting string? Assume no friction is present.}
-a) 45.8 N
-b) 52.6 N
-c) 60.5 N
-d) 69.6 N
+e) 80.1 N
===10===
{<!--a05frictDragElast_3rdLaw_1-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.4 kg, and the mass of m<sub>2</sub> is 3.7 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 135 N, what is the tension in the connecting string? Assume no friction is present.}
-a) 74.4 N
+b) 85.5 N
-c) 98.4 N
-d) 113.1 N
-e) 130.1 N
a05frictDragElast_3rdLaw_v1
copies
===2===
{<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 6.4 kg, m<sub>2</sub> = 2.3 kg, and F<sub>ext</sub> = 174 N), what is the acceleration? Assume no friction is present. }
+a) 20 m/s<sup>2</sup>
-b) 23 m/s<sup>2</sup>
-c) 26.5 m/s<sup>2</sup>
-d) 30.4 m/s<sup>2</sup>
-e) 35 m/s<sup>2</sup>
===3===
{<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 7 kg, m<sub>2</sub> = 3.6 kg, and F<sub>ext</sub> = 153 N), what is the acceleration? Assume no friction is present. }
-a) 12.6 m/s<sup>2</sup>
+b) 14.4 m/s<sup>2</sup>
-c) 16.6 m/s<sup>2</sup>
-d) 19.1 m/s<sup>2</sup>
-e) 22 m/s<sup>2</sup>
===4===
{<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 6.7 kg, m<sub>2</sub> = 2.5 kg, and F<sub>ext</sub> = 101 N), what is the acceleration? Assume no friction is present. }
-a) 6.3 m/s<sup>2</sup>
-b) 7.2 m/s<sup>2</sup>
-c) 8.3 m/s<sup>2</sup>
-d) 9.5 m/s<sup>2</sup>
+e) 11 m/s<sup>2</sup>
===5===
{<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 5.4 kg, m<sub>2</sub> = 3.9 kg, and F<sub>ext</sub> = 136 N), what is the acceleration? Assume no friction is present. }
-a) 12.7 m/s<sup>2</sup>
+b) 14.6 m/s<sup>2</sup>
-c) 16.8 m/s<sup>2</sup>
-d) 19.3 m/s<sup>2</sup>
-e) 22.2 m/s<sup>2</sup>
===6===
{<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 5.1 kg, m<sub>2</sub> = 2.8 kg, and F<sub>ext</sub> = 148 N), what is the acceleration? Assume no friction is present. }
-a) 14.2 m/s<sup>2</sup>
-b) 16.3 m/s<sup>2</sup>
+c) 18.7 m/s<sup>2</sup>
-d) 21.5 m/s<sup>2</sup>
-e) 24.8 m/s<sup>2</sup>
===7===
{<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 5.4 kg, m<sub>2</sub> = 2.3 kg, and F<sub>ext</sub> = 138 N), what is the acceleration? Assume no friction is present. }
-a) 10.2 m/s<sup>2</sup>
-b) 11.8 m/s<sup>2</sup>
-c) 13.6 m/s<sup>2</sup>
-d) 15.6 m/s<sup>2</sup>
+e) 17.9 m/s<sup>2</sup>
===8===
{<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 6.5 kg, m<sub>2</sub> = 2.5 kg, and F<sub>ext</sub> = 141 N), what is the acceleration? Assume no friction is present. }
-a) 9 m/s<sup>2</sup>
-b) 10.3 m/s<sup>2</sup>
-c) 11.8 m/s<sup>2</sup>
-d) 13.6 m/s<sup>2</sup>
+e) 15.7 m/s<sup>2</sup>
===9===
{<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 5.1 kg, m<sub>2</sub> = 3.5 kg, and F<sub>ext</sub> = 135 N), what is the acceleration? Assume no friction is present. }
-a) 13.7 m/s<sup>2</sup>
+b) 15.7 m/s<sup>2</sup>
-c) 18.1 m/s<sup>2</sup>
-d) 20.8 m/s<sup>2</sup>
-e) 23.9 m/s<sup>2</sup>
===10===
{<!--a05frictDragElast_3rdLaw_2-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown (with m<sub>1</sub> = 6.4 kg, m<sub>2</sub> = 3.7 kg, and F<sub>ext</sub> = 135 N), what is the acceleration? Assume no friction is present. }
+a) 13.4 m/s<sup>2</sup>
-b) 15.4 m/s<sup>2</sup>
-c) 17.7 m/s<sup>2</sup>
-d) 20.3 m/s<sup>2</sup>
-e) 23.4 m/s<sup>2</sup>
a05frictDragElast_3rdLaw_v1
copies
===2===
{<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 640 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.68 . The net mass of the (shoed) basketball team is 431 kg. What is the maximum coefficient of the barefoot boys if they lose?}
-a) 0.313
-b) 0.344
-c) 0.378
-d) 0.416
+e) 0.458
===3===
{<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 625 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.54 . The net mass of the (shoed) basketball team is 445 kg. What is the maximum coefficient of the barefoot boys if they lose?}
-a) 0.263
-b) 0.289
-c) 0.318
-d) 0.35
+e) 0.384
===4===
{<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 672 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.59 . The net mass of the (shoed) basketball team is 407 kg. What is the maximum coefficient of the barefoot boys if they lose?}
-a) 0.295
-b) 0.325
+c) 0.357
-d) 0.393
-e) 0.432
===5===
{<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 664 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.53 . The net mass of the (shoed) basketball team is 418 kg. What is the maximum coefficient of the barefoot boys if they lose?}
+a) 0.334
-b) 0.367
-c) 0.404
-d) 0.444
-e) 0.488
===6===
{<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 679 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.61 . The net mass of the (shoed) basketball team is 380 kg. What is the maximum coefficient of the barefoot boys if they lose?}
-a) 0.31
+b) 0.341
-c) 0.376
-d) 0.413
-e) 0.454
===7===
{<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 616 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.71 . The net mass of the (shoed) basketball team is 388 kg. What is the maximum coefficient of the barefoot boys if they lose?}
+a) 0.447
-b) 0.492
-c) 0.541
-d) 0.595
-e) 0.655
===8===
{<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 640 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.61 . The net mass of the (shoed) basketball team is 385 kg. What is the maximum coefficient of the barefoot boys if they lose?}
-a) 0.303
-b) 0.334
+c) 0.367
-d) 0.404
-e) 0.444
===9===
{<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 692 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.61 . The net mass of the (shoed) basketball team is 406 kg. What is the maximum coefficient of the barefoot boys if they lose?}
+a) 0.358
-b) 0.394
-c) 0.433
-d) 0.476
-e) 0.524
===10===
{<!--a05frictDragElast_3rdLaw_3-->Nine barefoot baseball players, with a total mass of 616 kg plays tug of war against five basketball players wearing shoes that provide a static coefficient of friction of 0.68 . The net mass of the (shoed) basketball team is 421 kg. What is the maximum coefficient of the barefoot boys if they lose?}
-a) 0.422
+b) 0.465
-c) 0.511
-d) 0.562
-e) 0.619
a05frictDragElast_3rdLaw_v1
copies
===2===
{<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.24 . But the team wins a game of tug of war due to their superior mass of 643 kg. They are playing against a 5 person basketball team with a net mass of 405 kg. What is the maximum coefficient of static friction of the basketball team? }
-a) 0.26
-b) 0.286
-c) 0.315
-d) 0.346
+e) 0.381
===3===
{<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.36 . But the team wins a game of tug of war due to their superior mass of 683 kg. They are playing against a 5 person basketball team with a net mass of 406 kg. What is the maximum coefficient of static friction of the basketball team? }
-a) 0.455
-b) 0.501
-c) 0.551
+d) 0.606
-e) 0.666
===4===
{<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.23 . But the team wins a game of tug of war due to their superior mass of 675 kg. They are playing against a 5 person basketball team with a net mass of 394 kg. What is the maximum coefficient of static friction of the basketball team? }
+a) 0.394
-b) 0.433
-c) 0.477
-d) 0.524
-e) 0.577
===5===
{<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.35 . But the team wins a game of tug of war due to their superior mass of 614 kg. They are playing against a 5 person basketball team with a net mass of 405 kg. What is the maximum coefficient of static friction of the basketball team? }
-a) 0.439
-b) 0.482
+c) 0.531
-d) 0.584
-e) 0.642
===6===
{<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.33 . But the team wins a game of tug of war due to their superior mass of 663 kg. They are playing against a 5 person basketball team with a net mass of 422 kg. What is the maximum coefficient of static friction of the basketball team? }
-a) 0.39
-b) 0.428
-c) 0.471
+d) 0.518
-e) 0.57
===7===
{<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.38 . But the team wins a game of tug of war due to their superior mass of 671 kg. They are playing against a 5 person basketball team with a net mass of 438 kg. What is the maximum coefficient of static friction of the basketball team? }
-a) 0.481
-b) 0.529
+c) 0.582
-d) 0.64
-e) 0.704
===8===
{<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.23 . But the team wins a game of tug of war due to their superior mass of 607 kg. They are playing against a 5 person basketball team with a net mass of 429 kg. What is the maximum coefficient of static friction of the basketball team? }
-a) 0.269
-b) 0.296
+c) 0.325
-d) 0.358
-e) 0.394
===9===
{<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.21 . But the team wins a game of tug of war due to their superior mass of 683 kg. They are playing against a 5 person basketball team with a net mass of 389 kg. What is the maximum coefficient of static friction of the basketball team? }
-a) 0.277
-b) 0.305
-c) 0.335
+d) 0.369
-e) 0.406
===10===
{<!--a05frictDragElast_3rdLaw_4-->Without their shoes, members of a 9 person baseball team have a coefficient of static friction of only 0.3 . But the team wins a game of tug of war due to their superior mass of 662 kg. They are playing against a 5 person basketball team with a net mass of 430 kg. What is the maximum coefficient of static friction of the basketball team? }
-a) 0.42
+b) 0.462
-c) 0.508
-d) 0.559
-e) 0.615
a05frictDragElast_3rdLaw_v1
copies
===2===
{<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.9 kg, and the mass of m<sub>2</sub> is 3 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 131 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.31, and that for m<sub>2</sub> the coefficient is 0.49 .}
-a) 76.2 N
+b) 87.6 N
-c) 100.8 N
-d) 115.9 N
-e) 133.3 N
===3===
{<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 5.7 kg, and the mass of m<sub>2</sub> is 3.1 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 137 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.34, and that for m<sub>2</sub> the coefficient is 0.47 .}
-a) 56.7 N
-b) 65.2 N
-c) 74.9 N
+d) 86.2 N
-e) 99.1 N
===4===
{<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 5.7 kg, and the mass of m<sub>2</sub> is 2.5 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 159 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.34, and that for m<sub>2</sub> the coefficient is 0.46 .}
-a) 82 N
-b) 94.3 N
+c) 108.5 N
-d) 124.8 N
-e) 143.5 N
===5===
{<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.9 kg, and the mass of m<sub>2</sub> is 2.5 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 165 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.35, and that for m<sub>2</sub> the coefficient is 0.44 .}
-a) 68.3 N
-b) 78.6 N
-c) 90.4 N
-d) 103.9 N
+e) 119.5 N
===6===
{<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.5 kg, and the mass of m<sub>2</sub> is 2.9 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 132 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.37, and that for m<sub>2</sub> the coefficient is 0.48 .}
+a) 89.1 N
-b) 102.5 N
-c) 117.9 N
-d) 135.5 N
-e) 155.9 N
===7===
{<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.8 kg, and the mass of m<sub>2</sub> is 3.3 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 112 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.39, and that for m<sub>2</sub> the coefficient is 0.46 .}
-a) 48.6 N
-b) 55.9 N
-c) 64.2 N
+d) 73.9 N
-e) 85 N
===8===
{<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6.5 kg, and the mass of m<sub>2</sub> is 3 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 175 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.33, and that for m<sub>2</sub> the coefficient is 0.48 .}
-a) 66.7 N
-b) 76.7 N
-c) 88.3 N
-d) 101.5 N
+e) 116.7 N
===9===
{<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 6 kg, and the mass of m<sub>2</sub> is 3.2 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 173 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.31, and that for m<sub>2</sub> the coefficient is 0.44 .}
+a) 110.2 N
-b) 126.7 N
-c) 145.7 N
-d) 167.6 N
-e) 192.7 N
===10===
{<!--a05frictDragElast_3rdLaw_5-->[[File:Forces 2 carts connected by string.jpg|right|340px]] In the figure shown, the mass of m<sub>1</sub> is 5.2 kg, and the mass of m<sub>2</sub> is 2.9 kg. If the external force, F<sub>ext</sub> on m<sub>2</sub> is 179 N, what is the tension in the connecting string? Assume that m<sub>1</sub> has a kinetic coefficient of friction equal to 0.36, and that for m<sub>2</sub> the coefficient is 0.46 .}
-a) 74.4 N
-b) 85.5 N
-c) 98.3 N
+d) 113.1 N
-e) 130.1 N
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