Exercises on the bisection method
Numerical analysis > Exercises on the bisection method
Exercise 1
- Write a Octave/MATLAB function for the bisection method. The function takes as arguments the function
, the extrema of the interval
and
, the tolerance
and the maximum number of iterations.
- Consider the function
in
.
- How many roots are there in this interval?
- Theoretically, how many iterations are needed to find a solution?
- With
, how many iterations are needed? Does the numerical result satisfy this condition?
- With
, how many iterations are needed? Does the numerical result satisfy this condition?
Exercise 2
- Consider the function
in
.
- Show the existence and uniqueness of the root
.
- Given the tolerance
, how many iterations are needed?
- Consideri the restriction of the interval to
. In this case how many iterations are needed?
- With the aid pf the Octave/MATLAB function of exercise 1, compute the root of the function.
- Compute the solution with precision
e consider it as the exact solution. Then considering
, draw a logarithmic plot to represent the average error and the actual error. Comment.
- Show the existence and uniqueness of the root
Exercise 3
Show that the sequence defined by the bisection method with we have
.
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