Boundary Value Problems/Lesson 5.1

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Lesson Plan

Requirements of student preparation: The student needs to have worked with vectors. If not the student should obtain suitable instruction in vector calculus.

Lesson on Vectors

We will be using only real numbers in this course. The set of all real numbers will be represented by  \mathcal{R} .

Definition of a scalar:

A scalar is a single real number,  \displaystyle a \in \mathcal{R} . For example  3 is a scalar.

Definition of a real vector:

A real vector, \displaystyle v is an ordered set of two or more real numbers.

For example:  \displaystyle v = (1,2) ,  \displaystyle w = (5,0,50,-1.25) are both vectors. We will use the notation of  \displaystyle v_i where the lower index  \displaystyle  i = 1..n represents the individual elements of a vector in the appropropriate order.

Ex: The vector  \displaystyle v=(3,-7) has two elements, the first element is designated  \displaystyle v_1=3 and the second is  \displaystyle v_2=-7

Dimension of a vector:

The dimension of a vector is the number of elements in the vector.

Ex: Dimension of  \displaystyle v = (-1.25, 0,-2,-2) is  n=4

Vector Operations:

To refresh your memory, for vectors of the same dimension the following are valid operations:
Let  v = (a,b) and  u=(c,d) for each of the following statements.

Ex:   v = (2,5) and  u=(6,1) then  v + w = (8,6)

Ex:  k =2 and  k (-2,4)=2(-2,4)=(-4,8)

Let 
\bold{u = (2,3,4) \mbox{ and } v = (-1,4,-3)} 
then
 \bold{u} \times \bold{v} =\left [ \begin{array}{ccc} i&j&k\\ 2&3&4
\\ -1&4&-3 
\end{array} \right ] = \bold{i}(3 (-3)- 4^2) - \bold{j} (2 (-3) -4 (-1)) + \bold{k} (2(4)- 3(-1)
 \bold{u} \times \bold{v} = -25 \bold{i} + \bold{j} + 11 \bold{k}

Lesson on Scalar and Vector Fields

Lesson on Solving Boundary Value Problems with Nonhomogeneous BCs

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