Computer Programming/Physics/Position of an accelerating body function

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The position of an accelerating body can be described by a mathematical function \mathbf{s}(t). The generalized function can be attained by using the Taylor series

\mathbf{s}(t+t_0)=\sum\frac{t^n}{n!}\mathbf{s}^{(n)}(t_0),

where \mathbf{s}^{(n)} is the nth derivative of \mathbf{s}:

  • \mathbf{s}^{(0)}=\frac{d^0\mathbf{s}}{dt^0}=\mathbf{s}
  • \mathbf{s}^{(1)}=\frac{d^1\mathbf{s}}{dt^1}=\mathbf{v}
  • \mathbf{s}^{(2)}=\frac{d^2\mathbf{s}}{dt^2}=\mathbf{a}
  • etc.

The accuracy of this function depends on the number of terms used as \frac{1}{n!} decreases rapidly. Additionally, the time t can be synchronized such that t_0=0 (Maclaurin series).

Note that for a constant acceleration most of the terms become zero and we're left with

s(t)=\frac{1}{0!}\mathbf{s}_0+\frac{t}{1!}\mathbf{s}^{(1)}_0+\frac{t^2}{2!}\mathbf{s}^{(2)}_0

or

\mathbf{s}(t)=\mathbf{s}_0+\mathbf{v}_0t+\frac{1}{2}\mathbf{a}t^2

C++

template<class Vector,class Number>
Vector PositionAcceleratingBody(Vector *s0,Number t,size_t Accuracy)
{
     Vector s(0);     //set to zero if int, float, etc. or invoke the
                      //     "set to zero" constructor for a class
     Number factor(1);//0!==1 and t^0==1
     for(size_t n(0);n<Accuracy;n++)
     {
          if(n)factor*=(t/n);//0!==1 and t^0==1
          s+=(factor*s0[n]); //s0 is the array of nth derivatives of s
                             //     at t=t0=0
     }
     return s;
}

Justification for Using the Taylor Series

The Taylor series can be derived by systematically selecting which of our variables is a constant and then extrapolating that to the infinite limit.

s(t)=s_0
or
s(t)=\frac{t^0}{0!}s^{(0)}(t_0=0)
v(t)=v_0
s(t)=\int vdt=\int v_0dt
s(t)=v_0t+s_0
or
s(t)=\frac{t^0}{0!}s^{(0)}(t_0=0)+\frac{t^1}{1!}s^{(1)}(t_0=0)
a(t)=a_0
v(t)=\int adt=\int a_0dt
v(t)=a_0t+v_0
s(t)=\int vdt=\int (a_0t+v_0)dt
s(t)=\frac{1}{2}a_0t^2+v_0t+s_0
or
s(t)=\frac{t^0}{0!}s^{(0)}(t_0=0)+\frac{t^1}{1!}s^{(1)}(t_0=0)+\frac{t^2}{2!}s^{(2)}(t_0=0)
a^{(1)}(t)=a^{(1)}_0
a(t)=\int a^{(1)}dt=\int a^{(1)}_0dt
a(t)=a^{(1)}_0t+a_0
v(t)=\int adt=\int (a^{(1)}_0t+a_0)dt
v(t)=\frac{1}{2}a^{(1)}_0t^2+a_0t+v_0
s(t)=\int vdt=\int (\frac{1}{2}a^{(1)}_0t^2+a_0t+v_0)dt
s(t)=\frac{1}{6}a^{(1)}_0t^3+\frac{1}{2}a_0t^2+v_0t+s_0
or
s(t)=\frac{t^0}{0!}s^{(0)}(t_0=0)+\frac{t^1}{1!}s^{(1)}(t_0=0)+\frac{t^2}{2!}s^{(2)}(t_0=0)+\frac{t^3}{3!}s^{(3)}(t_0=0)
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