Algebra/Arithmetic/Root Problem Answers

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Problem 1

${\sqrt {25}}$ or $25^{\left({\frac {1}{2}}\right)}$

Answer

$27^{\left({\frac {1}{3}}\right)}$ or ${\sqrt[{3}]{27}}$

Answer

$(27)^{\left({\frac {1}{3}}\right)}$ = 3 because (3*3*3) or $3^{3}$ = 27 then the cube root of 27 is 3.

${\sqrt[{4}]{648+648}}+8$ or $(648+648)^{\frac {1}{4}}+8$

Answer

${\sqrt[{4}]{1296}}+8=6+8=14$

$512^{\frac {2}{3}}$ or $({\sqrt[{3}]{512}})^{2}$

Answer

$(512)^{\frac {2}{3}}=(8)^{2}=64$

You take the root (denominator) first and then take the numerator.

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